Meryl Streep to receive the Golden Globes’ highest honor

BEVERLY HILLS, Calif., Nov. 3 (UPI) — Screen legend Meryl Streep is to be presented with the Cecil B. deMille Award at the 74th Golden Globes, the Hollywood Foreign Press Association announced Thursday.

Streep, 67, is already an eight-time Golden Globe winner. The deMille Award is a lifetime achievement honor previously bestowed on George Clooney, Woody Allen, Jodie Foster, Morgan Freeman, Robert De Niro, Martin Scorsese, Steven Spielberg, Warren Beatty, Anthony Hopkins, Robin Williams, Michael Douglas, Gene Hackman, Harrison Ford, Al Pacino and Barbra Streisand.

This year’s Golden Globes ceremony is set to take place Jan. 8. Jimmy Fallon will host the event at the Beverly Hilton Hotel. It will air on NBC.

“It’s no surprise that the HFPA has chosen Meryl Streep as the recipient of the 2017 Cecil B. DeMille Award,” Lorenzo Soria, the organization’s president, said in a statement. “Meryl’s enthralling body of work across a diverse set of genres has made her a role model over the past 40 years, and she will continue to do so for generations to come. She has always taken roles with strong female leads, creating art by showing vulnerability and portraying truth on the big screen. Simply put, she is a trailblazer, having paved the way for women in television, film and stage. For shattering gender and age barriers, all with finesse and grace, the HFPA is humbled to bestow this honor upon her.”